Algebra 1 · Reasoning with Equations & Inequalities

Choose graph/substitution/elimination

Choose graph/substitution/elimination.

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What you’ll learn

Choose graph/substitution/elimination.

Key idea

One point on one line does not justify a system solution; both relationships are required.

Graphing uses both constraints; another algebraic method can be valid, but a one-line or axis-swapped argument is not.

Worked example

Enter the exact value or ordered values in the format requested below.

Choose a justified method from the available exact graph: repeated R/B marks define full straight lines, C their crossing; x horizontal, y vertical.

-6-4-2024686420-2-4-6BBRRCRRBBxy

Marked coordinates: B=(-2, 9); B=(-1, 5); R=(2, 5); R=(1, 3); C=(0, 1); R=(-1, -1); R=(-2, -3); B=(1, -3); B=(2, -7).

  1. The fully labeled graph has a unique exact crossing at (0,1), so graphing supplies a direct method using the given representation.
  2. Check both equations at that crossing: 2(0)+1=1 and -4(0)+1=1. Two points per line including the crossing justify the construction.

Answer: Graphing

Quick Check

Relate the graph used in 'Choose graph/substitution/elimination' to an equation, table, transformation, or verbal description.

For R: y=2x+4; B: y=-3x-1, connect this exact labeled graph to a method AND complete solution. C is shared, x horizontal, y vertical.

-6-4-2024686420-2-4-6BRBRCRBRBxy

Marked coordinates: B=(-3, 8); R=(1, 6); B=(-2, 5); R=(0, 4); C=(-1, 2); R=(-2, 0); B=(0, -1); R=(-3, -2); B=(1, -4).

Choose one answer

Show a hint

Choose a method that uses the available exact intersection information.